Remember we are discussing probabilities, not practicalities. If you want to calculate the probability of the BG being in one of the 20 cars (without giving credence to the tip) you can't ignore the probability that he wouldn't be there at all. It may be silly to you but you can't properly calculate the probability any other way.sjfcontrol wrote:Well, that's obviously a different problem all together. Conceptually that could then involve the search of every car in the entire town -- and that assumes that they could throw up road-blocks at all egresses before the vehicle could have exited the town. Now we're just getting silly (not that the original solution wasn't). There's no way they could stop everybody in a vehicle in the whole town. There wouldn't be enough cops (or handcuffs, for that matter). Seems to me they either had to find him at the intersection in question, or he was 'in the wind'.jmra wrote: It changes the odds because if you rightly assume that the BG may not be in one of the 20 cars then you are no longer limiting the probabilities to 20 cars. You would have to calculate how far the BG could have traveled in every route available to him. Then you would have to estimate the total number of vehicles in that area. Then you would use that number in relationship to the 20 cars that were stopped to determine the probability that he was even in one of the 20 cars. Unless of course you believe that the tip was iron clad.
Now, if you want to qualify that the tip assures that one of the 20 cars contains the BG, then that is a different story.